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Eessteellee
@Eessteellee
April 2019
1
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Aidez moi Svp !
développer les deux expression suivantes :
A= (6-x) au carré
B=(6-x)(4-x)
donner l'écriture développer et réduite de:
E=(6-x )au carré-(6-x)(4-x)+2(36-xaucarré)
et factoriser E
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Orie
A= (6-x)² = (6-x)(6-x) = 36-6x-6x+x² = 36-12x+x²
B= (6-x)(4-x) = 24-6x-4x+x² = 24-10x+x²
E=(6-x)²-(6-x)(4-x)+2(36-x²) = 36-12x+x²-(24-10x+x²)+72-2x²
= 36-12x+x²-24+10x-x²+72-2x²
= 84-2x-2x²
E=(6-x)²-(6-x)(4-x)+2(36-x²) = (6-x)²-(6-x)(4-x)+2[(6-x)(6+x)]
= (6-x)[(6-x)-(4-x)+2(6+x)]
= (6-x)(6-x-4+x+12+2x)
= (6-x)(15+2x)
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S'il vous plait c pour demain et je ne comprend pas pouvez vousv m'aidez c'est urgent !!!!!! l'exercice es ci dessous merci d'avance
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B= (6-x)(4-x) = 24-6x-4x+x² = 24-10x+x²
E=(6-x)²-(6-x)(4-x)+2(36-x²) = 36-12x+x²-(24-10x+x²)+72-2x²
= 36-12x+x²-24+10x-x²+72-2x²
= 84-2x-2x²
E=(6-x)²-(6-x)(4-x)+2(36-x²) = (6-x)²-(6-x)(4-x)+2[(6-x)(6+x)]
= (6-x)[(6-x)-(4-x)+2(6+x)]
= (6-x)(6-x-4+x+12+2x)
= (6-x)(15+2x)