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Leaguerre01
@Leaguerre01
May 2019
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Aidez moi SVP : exercice 48
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nadiab
F(x) = ax +b
A(0;0) B(-2;3)
a=3-0/-2-0
a=-3/2
f(-2)=3
-3/2(-2)+b=3
6/2+b=3
b=3-3
b=0
f(x)=-3/2x
f(x)= ax+b
A(0;4) B(4;0) tu procèdes de la même manière
f(x)=ax+b
A(-5;3) B(-10;6)
a=6-3/-10-(-5)
a=3/-5
f(-5)=3
-3/5(-5)+b=3
15/3+b=3
b=3-5
b=-2
donc
f(x)=-3/5x-2
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A(0;0) B(-2;3)
a=3-0/-2-0
a=-3/2
f(-2)=3
-3/2(-2)+b=3
6/2+b=3
b=3-3
b=0
f(x)=-3/2x
f(x)= ax+b
A(0;4) B(4;0) tu procèdes de la même manière
f(x)=ax+b
A(-5;3) B(-10;6)
a=6-3/-10-(-5)
a=3/-5
f(-5)=3
-3/5(-5)+b=3
15/3+b=3
b=3-5
b=-2
donc f(x)=-3/5x-2