Aidez moi svp, il faut calculer Delta (b²-4ac)+ les solutions de -0.03x² +0.2x +133.... Pergunta de ideia denikitaa

nikitaa @nikitaa

June 2021 1 71 Report

Aidez moi svp, il faut calculer Delta (b²-4ac)+ les solutions de -0.03x² +0.2x +133

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Steffy1 Bonjour !!!! :)

f(x)= -0,03²+0,2x+133

a=-0,03 b=0,2 c=133

Δ=b² -4ac

Δ=0,2² -4×(-0,03)×133
Δ=0,04+1596
Δ=16

Delta admet 2 solutions:

$x_{1} = \frac{-b+ \sqrt{delta} }{2a}$ $x_{2}= \frac{-b- \sqrt{delta} }{2a}$
$x_{1} = \frac{-0,2+ \sqrt{16} }{2*(-0,03) } \\ x_{1}= \frac{3,8}{-0,06} \\ x_{1} =-63,33$ $x_{2} = \frac{-0,2- \sqrt{16} }{2*a} \\ x_{2} = \frac{-4,2}{-0,06} \\ x_{2}= 70$

Voila !!! ^^

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