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dianatavares
@dianatavares
June 2021
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AIDEZ MOI SVP JE VOUS EN SUPLIE
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tiitine
1) ACB = 1/2 AOB = 1/2(50) = 25
CAB = 1/2 BOC = 1/2 (108) = 54
ABC = 180 - (25 + 54 ) = 101
autre méthode pourl'angle ABC
:
dans le triangle AOB on a OA = OB donc l'angle OAB = OBA = (180-50)/2 = 65
dans le triangle COB on a OB = OC donc l'angle OCB = OBC = (180-108)/2 = 36
on sais que l'angle ABC = OBA + OBC = 65 + 36 = 101
2) l'angle ABC = ADC = 101
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dianatavares
MERCI ENORMEMENT
Lola3434
Déjà répondu sur ton autre question :
Pour la 1ère question : si un angle au centre et un angle inscrit ont le même arc de cercle alors l'angle au centre mesure le double de l'angle inscrit. AOB = 2 x ACB = AOB/2 = 50/2 = 25°
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CAB = 1/2 BOC = 1/2 (108) = 54
ABC = 180 - (25 + 54 ) = 101
autre méthode pourl'angle ABC:
dans le triangle AOB on a OA = OB donc l'angle OAB = OBA = (180-50)/2 = 65
dans le triangle COB on a OB = OC donc l'angle OCB = OBC = (180-108)/2 = 36
on sais que l'angle ABC = OBA + OBC = 65 + 36 = 101
2) l'angle ABC = ADC = 101
Pour la 1ère question : si un angle au centre et un angle inscrit ont le même arc de cercle alors l'angle au centre mesure le double de l'angle inscrit. AOB = 2 x ACB = AOB/2 = 50/2 = 25°