Verified answer

Explications étape par étape:

factoriser

A=(3x-1)(x-2)+(2x-3)(2-x)

A=(3x-1)(x-2)+(2x-3)(-x+2)

A=(3x-1)(x-2)+[-(-2x+3)(x-2)]

A=(3x-1)(x-2) - (-2x+3)(x-2)

A=(x-2)[(3x-1)-(-2x+3)]

A=(x-2)(3x-1+2x-3)

A=(x-2)(5x-4)

B=(5x-1)(3x+2)-(1-5x)(4x-3)

B=(5x-1)(3x+2)-(-5x+1)(4x-3)

B=(5x-1(3x+2)-[-(5x-1)(4x-3)]

B=(5x-1)[(3x+2)+(4x-3)]

B=(5x-1)(3x+2+4x-3)

B=(5x-1)(7x-1)

C=(12x-16)(x-3)-(4-3x)(x+5)

C=[4(3x-4)(x-3)]-(-3x+4)(x+5)

C=4(3x-4)(x-3)-[-(3x-4)(x+5)]

C=4(3x-4)(x-3)+(3x+4)(x+5)

C=(3x-4)[4(x-3)+(x+5)]

C=(3x-4)[4x-12+x+5)]

C=(3x-4)(5x-7)

D=(4x+1)²+(4x+1)

D=(4x+1)(4x+1)+(4x+1)

D=(4x+1)(4x+1)+1

D=(4x+1)(4x+1+1)

D=(4x+1)(4x+2)

E=(3x-1)(x-3)-(x-3)

E=(x-3)(3x-1)-1

E=(x-3)(3x-1-1)

E=(x-3)(3x-2)

F=(x-7)-(x-7)²

F=(x-7)(1-(x-7))

F=(x-7)(x-6)