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EloHanerJericho
@EloHanerJericho
April 2019
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aidez moi SVP URGENT!!!!
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1) RF=18-1,5
RF=16,5 m
2) tan(FPR)=16,5/18
donc FPR=42,51°
3) th de Pythagore
FP²=FR²+RP²
=16,5²+10²
=372,25
FP=19,29 m < 25 m
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Lista de comentários
RF=16,5 m
2) tan(FPR)=16,5/18
donc FPR=42,51°
3) th de Pythagore
FP²=FR²+RP²
=16,5²+10²
=372,25
FP=19,29 m < 25 m