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DeboraPaula
@DeboraPaula
March 2022
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ALGUÉM ME AJUDA A RESOLVER URGENTE???
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EvertonPrado10
Log4 (2/log16(4)) + log4 (√2) + log100 (√0,001) log 1/9 (3√3) =
log4(2) - log16 (4) + log4 (√2) + log100( √10^-3) + log1/9 (3√3) =
log2²(2) - log4² (4) + log2² (√2) + log10² (√10^-3) + log 3^-2 (3√3)=
1/2 - 1/2 + 1/2log2(2^1/2) + 1/2log10 (10^-3/2) -1/2 log3 (3√3)=
1/4 - 3/4 - 1/2log3 (3) -1/2log3(√3) =
1/4 - 3/4 - 1/2 - 1/4 =
-5/4
entao o valor numerico dela e 3/2 ou seja três sobre dois.
2 votes
Thanks 1
DeboraPaula
Não entendi pq a resposta deu -5/4 e vc falou que ela virou 3/2???
EvertonPrado10
desculpe errei a conta, a resolução correta é:
EvertonPrado10
http://brainly.com.br/tarefa/971503
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log4(2) - log16 (4) + log4 (√2) + log100( √10^-3) + log1/9 (3√3) =
log2²(2) - log4² (4) + log2² (√2) + log10² (√10^-3) + log 3^-2 (3√3)=
1/2 - 1/2 + 1/2log2(2^1/2) + 1/2log10 (10^-3/2) -1/2 log3 (3√3)=
1/4 - 3/4 - 1/2log3 (3) -1/2log3(√3) =
1/4 - 3/4 - 1/2 - 1/4 =
-5/4
entao o valor numerico dela e 3/2 ou seja três sobre dois.