Articles
Register
Sign In
Search
DeboraPaula
@DeboraPaula
March 2022
1
36
Report
ALGUÉM ME AJUDA A RESOLVER URGENTE???
Please enter comments
Please enter your name.
Please enter the correct email address.
Agree to
terms and service
You must agree before submitting.
Send
Lista de comentários
EvertonPrado10
Log4 (2/log16(4)) + log4 (√2) + log100 (√0,001) log 1/9 (3√3) =
log4(2) - log16 (4) + log4 (√2) + log100( √10^-3) + log1/9 (3√3) =
log2²(2) - log4² (4) + log2² (√2) + log10² (√10^-3) + log 3^-2 (3√3)=
1/2 - 1/2 + 1/2log2(2^1/2) + 1/2log10 (10^-3/2) -1/2 log3 (3√3)=
1/4 - 3/4 - 1/2log3 (3) -1/2log3(√3) =
1/4 - 3/4 - 1/2 - 1/4 =
-5/4
entao o valor numerico dela e 3/2 ou seja três sobre dois.
2 votes
Thanks 1
DeboraPaula
Não entendi pq a resposta deu -5/4 e vc falou que ela virou 3/2???
EvertonPrado10
desculpe errei a conta, a resolução correta é:
EvertonPrado10
http://brainly.com.br/tarefa/971503
More Questions From This User
See All
DeboraPaula
April 2022 | 0 Respostas
Responda
DeboraPaula
April 2022 | 0 Respostas
alguem sabe resolver urgente
Responda
DeboraPaula
April 2022 | 0 Respostas
Responda
DeboraPaula
April 2022 | 0 Respostas
Responda
DeboraPaula
March 2022 | 0 Respostas
me ajude urgente estou em duvida se marco a letra d ou e????
Responda
DeboraPaula
March 2022 | 0 Respostas
urgente.............................................
Responda
DeboraPaula
March 2022 | 0 Respostas
Responda
DeboraPaula
March 2022 | 0 Respostas
Responda
DeboraPaula
March 2022 | 0 Respostas
Responda
DeboraPaula
March 2022 | 0 Respostas
Responda
×
Report "ALGUÉM ME AJUDA A RESOLVER URGENTE???.... Pergunta de ideia de DeboraPaula"
Your name
Email
Reason
-Select Reason-
Pornographic
Defamatory
Illegal/Unlawful
Spam
Other Terms Of Service Violation
File a copyright complaint
Description
Helpful Links
Sobre nós
Política de Privacidade
Termos e Condições
direito autoral
Contate-Nos
Helpful Social
Get monthly updates
Submit
Copyright © 2024 ELIBRARY.TIPS - All rights reserved.
Lista de comentários
log4(2) - log16 (4) + log4 (√2) + log100( √10^-3) + log1/9 (3√3) =
log2²(2) - log4² (4) + log2² (√2) + log10² (√10^-3) + log 3^-2 (3√3)=
1/2 - 1/2 + 1/2log2(2^1/2) + 1/2log10 (10^-3/2) -1/2 log3 (3√3)=
1/4 - 3/4 - 1/2log3 (3) -1/2log3(√3) =
1/4 - 3/4 - 1/2 - 1/4 =
-5/4
entao o valor numerico dela e 3/2 ou seja três sobre dois.