Resposta:

c)

[tex] \frac{3x + 3}{4} = \frac{2}{3} \\ \\ \frac{3x + 3}{4} - \frac{2} {3} = 0 \\ \\ \frac{9x + 9 - 8}{12} = 0 \\ \\ \frac{9x + 1}{12} = 0 \\ \\ 9x + 1 = 0 \\ 9x = - 1 \\ x = - \frac{1}{9} [/tex]

[tex] \frac{4x + 2}{4} = 8 \\ \\ \frac{4x + 2}{4} - 8 = 0 \\ \\ \frac{4x + 2 - 32}{4} = 0 \\ \\ 4x + 2 - 32 = 0 \\ 4x - 30 = 0 \\ 4x = 30 \\ \\ x = \frac{30}{4} \div (2) \\ \\ x = \frac{15}{2} [/tex]