October 2020 0 72 Report
Alguém pode me ajudar nesta conta por obséquio? 2√3 ÷ sen 60°= C ÷ sen 45°?
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Por favor preciso das repostas para hoje: Considerando log2=0,3, log3=0,5 e log5=0,7, determine o valor de: log 1,2; (log1,5)^2 e log raiz 0,3-0,25.
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