Verified answer

[tex]\LARGE\tt{} \dfrac{3x + 3}{4} = \dfrac{2}{3} \\ \\ \LARGE\tt{}3(3x + 3) = 8 \\ \LARGE\tt{}9x + 9 = 8 \\ \LARGE\tt{}9x = 8 - 9 \\ \LARGE\tt{}9x = - 1 \\ \LARGE\tt{}x = - \dfrac{1}{9} \\ \\ {\large\boxed{\boxed{  { \LARGE \tt x = - \dfrac{1}{9} }}}}[/tex]

[tex]{\large\boxed{\boxed{  { \large \tt Bons~Estudos~! }}}}[/tex]