Articles
Register
Sign In
Search
Hackert
@Hackert
April 2022
1
31
Report
Alguém ? ............
Please enter comments
Please enter your name.
Please enter the correct email address.
Agree to
terms and service
You must agree before submitting.
Send
Lista de comentários
AlexFranca
X = 1, y = 3 e z = 2
(x/2 + y/3 + z/4) / (x/4 + y/3 + z/2)
(1/2 + 3/3 + 2/4) / (1/4 + 3/3 + 2/2)
(1/2 + 1 + 1/2) / (1/4 + 1 + 1)
2/ (1/4 + 8/4)
2/ (9/4)
2 * 4/9
8/9
1 votes
Thanks 1
Hackert
O.o Gj
Hackert
Muito bom :D
Hackert
Pena que estou com dificuldades para entender .. mais resposta correta ;D
Hackert
CAra ?
Hackert
(1/2 + 1 + 1/2) / (1/4 + 1 + 1)
2/ (1/4 + 8/4)
2/ (9/4)
2 * 4/9
8/9
Hackert
Explica essa parte aqui :D
More Questions From This User
See All
Hackert
April 2022 | 0 Respostas
Responda
Hackert
April 2022 | 0 Respostas
Responda
×
Report "Alguém ? .... Pergunta de ideia de Hackert"
Your name
Email
Reason
-Select Reason-
Pornographic
Defamatory
Illegal/Unlawful
Spam
Other Terms Of Service Violation
File a copyright complaint
Description
Helpful Links
Sobre nós
Política de Privacidade
Termos e Condições
direito autoral
Contate-Nos
Helpful Social
Get monthly updates
Submit
Copyright © 2024 ELIBRARY.TIPS - All rights reserved.
Lista de comentários
(x/2 + y/3 + z/4) / (x/4 + y/3 + z/2)
(1/2 + 3/3 + 2/4) / (1/4 + 3/3 + 2/2)
(1/2 + 1 + 1/2) / (1/4 + 1 + 1)
2/ (1/4 + 8/4)
2/ (9/4)
2 * 4/9
8/9
2/ (1/4 + 8/4)
2/ (9/4)
2 * 4/9
8/9