BESOIN D AIDE
je n'arrive pas a repondre a la question
3.4 et 3.5 de l'exercice n 1
svp merci
je n'arrive pas a repondre a la question
3.4 et 3.5 de l'exercice n 1
svp merci
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M(C₁₄H₁₇O₅N₂) = 14MC+17M(H)+5M(O)+2(N))
M(C₁₄H₁₇O₅N₂) = 14x12+17x1+5x16+2x14
M(C₁₄H₁₇O₅N₂) = 293 g/mol
3.4.
n = m/M
n = 0,001/293
n = 3,41x10⁻⁶ mol
3.5.
C = n/V
C = 3,41x10⁻⁶/0,0,33 V = 33 cL = 0,33 L
C = 1,03x10⁻⁵ mo/L