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Amira94
@Amira94
June 2021
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besoin d'aide svp pour l'exercice 1 , 2 et 3
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winner123
Verified answer
Bonjour
Exercice I
5 x ( - 4 x +12) = - 20 x² + 60
-6 ( 3 y +15) = - 18 y - 90
5 x +3 ( - 6x +10) - 20 = 5 x - 18 x + 30 -20 = - 13 x + 10
Exercice II
3 x +5 = 7 x -4
3 x - 7 x = - 4 -5
- 4 x = -9
x = 9/4
10 x = 2 x +7
10 x - 2 x = 7
8 x = 7
x = 7/8
- 4 x + 7 = 3 x -10
- 4 x - 3 x = - 10 -7
- 7 x = - 17
x = 17/7
32 = 5 x + 18
32 -18 = 5 x
14 = 5 x
x = 14/5
7 x +28 = 7 ( x + 4)
9 x² +12 = 3 ( 3 x² +4)
13 x² - 7 x = x ( 13 x - 7)
4( x +2) - 8 x ( x +2) = ( x +2) ( 4 - 8 x )
Exercice III
calcul de Charlotte
8 x +7
calcul de Arthur
10 x -2
8 x +7 = 10 x -2
8 x - 10 x = - 2 -7
- 2x = -9
x = 9/2 = 4,5
ils ont choisi 4, 5
1 votes
Thanks 1
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Amira94
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Svp ! j'ai besoin d'aide
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pouvez vous m'aider sur l'exercice 2 svp
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besoin d'aide pour la question 3 et 4
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Bonjour j'aimerais avoir de l'aide pour les questions 1 et 2 (avec l'aide des documents 1 , 2 et 3)
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Besoin d'aide pour cette exercice svp Exercice 1 : Deux affirmations sont donnees ci-dessous. Pour chacune, indiquer si elle est vraie ou fausse en argumentant la reponse. 1) Deux nombres impairs sont toujours premiers entre eux 2) Pour n'importe quel nombre entier n , 5n (2n - 12) est un multiple de 10
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BonjourExercice I
5 x ( - 4 x +12) = - 20 x² + 60
-6 ( 3 y +15) = - 18 y - 90
5 x +3 ( - 6x +10) - 20 = 5 x - 18 x + 30 -20 = - 13 x + 10
Exercice II
3 x +5 = 7 x -4
3 x - 7 x = - 4 -5
- 4 x = -9
x = 9/4
10 x = 2 x +7
10 x - 2 x = 7
8 x = 7
x = 7/8
- 4 x + 7 = 3 x -10
- 4 x - 3 x = - 10 -7
- 7 x = - 17
x = 17/7
32 = 5 x + 18
32 -18 = 5 x
14 = 5 x
x = 14/5
7 x +28 = 7 ( x + 4)
9 x² +12 = 3 ( 3 x² +4)
13 x² - 7 x = x ( 13 x - 7)
4( x +2) - 8 x ( x +2) = ( x +2) ( 4 - 8 x )
Exercice III
calcul de Charlotte
8 x +7
calcul de Arthur
10 x -2
8 x +7 = 10 x -2
8 x - 10 x = - 2 -7
- 2x = -9
x = 9/2 = 4,5
ils ont choisi 4, 5