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canyouhelpmeplz5
@canyouhelpmeplz5
January 2021
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Bjr j'aurait besoin d'aide pr se devoir svp merci
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nini999
Verified answer
Bonjour :
On a : le triangle EDF est rectangle en F
Et : DF = 7 cm
: FE = b
: DE = b + 5
D'après la propriété de Pythagore :
Alors :
DE² = DF² + FE²
(b + 5)² = 7² + b²
b² = (b + 5)² - 7²
b² = (b² + 10b + 25) - 49
b² = b² + 10b + 25 - 49
b² = b² + 10b - 24
b² - b² - 10b = -24
0 - 10b = -24
-10b = -24
b = -24/-10
b = 24/10
b = 2.4 cm
J’espère t'avoir t'aider
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Verified answer
Bonjour :On a : le triangle EDF est rectangle en F
Et : DF = 7 cm
: FE = b
: DE = b + 5
D'après la propriété de Pythagore :
Alors :
DE² = DF² + FE²
(b + 5)² = 7² + b²
b² = (b + 5)² - 7²
b² = (b² + 10b + 25) - 49
b² = b² + 10b + 25 - 49
b² = b² + 10b - 24
b² - b² - 10b = -24
0 - 10b = -24
-10b = -24
b = -24/-10
b = 24/10
b = 2.4 cm
J’espère t'avoir t'aider