Ex1
1) F=((2x)²+12x+3²)-(2x²+3x+10x+15)=(4x²+12x+9)-(2x²+13x+15)=4x²+12x+9-2x²-13x-15=2x²-x-6
2) F= (2x+3)(2x+3-x-5)=(2x+3)(x-2)
3) (2x+3)(x-2)=0
2x+3=0 ou x-2=0
2x=-3 ou x=2
x=-3/2 ou x=2
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Ex1
1) F=((2x)²+12x+3²)-(2x²+3x+10x+15)=(4x²+12x+9)-(2x²+13x+15)=4x²+12x+9-2x²-13x-15=2x²-x-6
2) F= (2x+3)(2x+3-x-5)=(2x+3)(x-2)
3) (2x+3)(x-2)=0
2x+3=0 ou x-2=0
2x=-3 ou x=2
x=-3/2 ou x=2