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maxime1504
@maxime1504
January 2021
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Bonjour à tous,
je ne comprend pas l'exercice 4. Pouvez-vous m'aider SVP.
Merci.
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AhYan
Bonjour,
f(x) = 2x² - 3x + 1
Donc on a :
f(n+1) = 2(n+1)² - 3(n+1) + 1
f(n+1) = 2(n²+2n+1) - (3n+3) + 1
f(n+1) = 2n²+4n+2 - 3n - 3 + 1
f(n+1) = 2n²+n
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f(x) = 2x² - 3x + 1
Donc on a :
f(n+1) = 2(n+1)² - 3(n+1) + 1
f(n+1) = 2(n²+2n+1) - (3n+3) + 1
f(n+1) = 2n²+4n+2 - 3n - 3 + 1
f(n+1) = 2n²+n