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abdlskn
@abdlskn
January 2021
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Bonjour à tous
Pouvez vous m'aider à calculer cette intégral ?
Merci d'avance
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laurance
F(x)=(2x^4+2x^2 +3)/x^2 = 2x^2 + 2 + 3/x^2
F(x)=2/3*x^3 +2x - 3/x
F(5)=2/3*125 +10 - 3/5 = 1391/15
Integrale = F(t) - F(5)= 2/3*t^3 +2t - 3/t - 1391/15
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Thanks 1
abdlskn
ce n'esr pas plutôt 3x pour ma primitive au lieu de 3 ?
abdlskn
enfaite non c'est bon j'ai compris
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F(x)=2/3*x^3 +2x - 3/x
F(5)=2/3*125 +10 - 3/5 = 1391/15
Integrale = F(t) - F(5)= 2/3*t^3 +2t - 3/t - 1391/15