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Eli3
@Eli3
May 2019
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Bonjour aidé moi svp svp ex 73
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rosiemuller2000
Verified answer
Coucou
1) le triangle ABC est rectangle en C
l egalite de pythagore est vraie
BA²=AC²+BC²
30²=25²+BC²
30²-25²=BC²
= BC
5√11 = BC
2)
le triangle ACD est rectangle en C on peut donc utliser la trigo
tan49 = CD/25
tan49 * 25 = CD
28,7 cm ≈ CD
BD = BC+CD
BD ≈ 5√11 + 28,7
BD ≈ 45,2831 cm
BD ≈ 453 mm
voila j espere t avoir aider
2 votes
Thanks 1
eli3
merci bcp
rosiemuller2000
de rien ;)
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Verified answer
Coucou1) le triangle ABC est rectangle en C
l egalite de pythagore est vraie
BA²=AC²+BC²
30²=25²+BC²
30²-25²=BC²
5√11 = BC
2)
le triangle ACD est rectangle en C on peut donc utliser la trigo
tan49 = CD/25
tan49 * 25 = CD
28,7 cm ≈ CD
BD = BC+CD
BD ≈ 5√11 + 28,7
BD ≈ 45,2831 cm
BD ≈ 453 mm
voila j espere t avoir aider