Articles
Register
Sign In
Search
Pikachu972
@Pikachu972
April 2019
2
96
Report
Bonjour , Aidez-moi s'il vous plaît à factoriser .
Factorisez l'expression suivante :
( 2x+1)² - ( 2x+1) (x+3) = ( 2x+1) ( x+3) .
Normalement le facteur est (2x+1) mais je veux factoriser cette expression .
Please enter comments
Please enter your name.
Please enter the correct email address.
Agree to
terms and service
You must agree before submitting.
Send
Lista de comentários
raymrich
Bonjour,
(2x+1)²-(2x+1)(x+3)-(2x+1)(x+3) = 0⇔
Le facteur commun est (2x+1)
Donc (2x+1)[2x+1-(x+3)-(x+3)] = (2x+1)(2x+1-x-3-x-3) = (2x+1)(-5) = -5(2x+1) = 0
1 votes
Thanks 1
Pikachu972
merci
anomaarieljonathan
J'écris directement la réponse:
( 2x+1 ) ( 2x+1 ) - ( 2x+1 ) ( x+3 ) - ( 2x+1 ) ( x+3 ) = 0
( 2x+1 ) [ ( 2x+1 ) - ( x+3 ) - ( x+3 ) ] = 0
( 2x+1 ) ( 2x + 1 - x - 3 - x - 3 ) = 0
( 2x+1 ) ( 2x - x - x - 3 - 3 + 1 ) = 0
( 2x+1 ) ( 2x - 2x - 6 + 1 ) = 0
( 2x+1 ) ( 0 - 5 ) = 0
( 2x+1 ) ( - 5 ) = 0
- 5 ( 2x+1 ) = 0
( 2x+1 ) = 0 / - 5
( 2x + 1 ) = 0
2x + 1 = 0
2x = - 1
x = - 1 / 2
2 votes
Thanks 1
Pikachu972
merci
More Questions From This User
See All
Pikachu972
February 2021 | 0 Respostas
Responda
Pikachu972
February 2021 | 0 Respostas
Responda
Pikachu972
February 2021 | 0 Respostas
Responda
Pikachu972
February 2021 | 0 Respostas
Responda
Pikachu972
February 2021 | 0 Respostas
Bonjour , je n' arrive pas , votre aide sera la bien venue !
Responda
Pikachu972
February 2021 | 0 Respostas
Responda
Pikachu972
February 2021 | 0 Respostas
Responda
Pikachu972
February 2021 | 0 Respostas
Responda
Pikachu972
January 2021 | 0 Respostas
Responda
Pikachu972
January 2021 | 0 Respostas
Responda
×
Report "Bonjour , Aidez-moi s'il vous plaît à factoriser . Factorisez l'expression suivante : ( 2x+1)² - (.... Pergunta de ideia de Pikachu972"
Your name
Email
Reason
-Select Reason-
Pornographic
Defamatory
Illegal/Unlawful
Spam
Other Terms Of Service Violation
File a copyright complaint
Description
Helpful Links
Sobre nós
Política de Privacidade
Termos e Condições
direito autoral
Contate-Nos
Helpful Social
Get monthly updates
Submit
Copyright © 2024 ELIBRARY.TIPS - All rights reserved.
Lista de comentários
(2x+1)²-(2x+1)(x+3)-(2x+1)(x+3) = 0⇔
Le facteur commun est (2x+1)
Donc (2x+1)[2x+1-(x+3)-(x+3)] = (2x+1)(2x+1-x-3-x-3) = (2x+1)(-5) = -5(2x+1) = 0
( 2x+1 ) ( 2x+1 ) - ( 2x+1 ) ( x+3 ) - ( 2x+1 ) ( x+3 ) = 0
( 2x+1 ) [ ( 2x+1 ) - ( x+3 ) - ( x+3 ) ] = 0
( 2x+1 ) ( 2x + 1 - x - 3 - x - 3 ) = 0
( 2x+1 ) ( 2x - x - x - 3 - 3 + 1 ) = 0
( 2x+1 ) ( 2x - 2x - 6 + 1 ) = 0
( 2x+1 ) ( 0 - 5 ) = 0
( 2x+1 ) ( - 5 ) = 0
- 5 ( 2x+1 ) = 0
( 2x+1 ) = 0 / - 5
( 2x + 1 ) = 0
2x + 1 = 0
2x = - 1
x = - 1 / 2