(4x+3)(2x+5) = 8x²+20x+6x+15=8x²+26x+15
x=0 alors 8*0² + 26*0+15= 0
X=1 alors 8+26+15= 49
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(4x+3)(2x+5) = 8x²+20x+6x+15=8x²+26x+15
x=0 alors 8*0² + 26*0+15= 0
X=1 alors 8+26+15= 49