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Intello2000
@Intello2000
April 2019
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Bonjour ! Aidez moi SVP ! ;) --> 80
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moimoimoimoimoi
Exercice 80 :
1)
D= (2x+3)² + (x-5)(2x+3)
D= (2x)² + 2*2x*3 + 3² + 2x² + 3x - 10x - 15
D= 4x² + 12x + 9 + 2x² + 3x - 10x - 15
D= 6x² + 5x -6
2)
D= (2x+3)² + (x-5)(2x+3)
D=
(2x+3)
(2x+3) + (x-5)
(2x+3)
D=
(2x+3)
[(2x+3)+(x-5)]
D=
(2x+3)
[2x+3+x-5]
D=
(2x+3)
(3x-2)
3) Si un produit est nul alors l'un au moins des facteurs est nul
(2x+3)(3x-2)=0
2x+3 = 0 3x-2=0
2x+3-3=0-3 3x-2+2=0+2
2x=-3 3x=2
x=-3/2
x=2/3
x=-1,5
L'équation a deux solutions: x = -1,5 et 2/3
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1)
D= (2x+3)² + (x-5)(2x+3)
D= (2x)² + 2*2x*3 + 3² + 2x² + 3x - 10x - 15
D= 4x² + 12x + 9 + 2x² + 3x - 10x - 15
D= 6x² + 5x -6
2)
D= (2x+3)² + (x-5)(2x+3)
D= (2x+3)(2x+3) + (x-5)(2x+3)
D= (2x+3)[(2x+3)+(x-5)]
D= (2x+3)[2x+3+x-5]
D= (2x+3)(3x-2)
3) Si un produit est nul alors l'un au moins des facteurs est nul
(2x+3)(3x-2)=0
2x+3 = 0 3x-2=0
2x+3-3=0-3 3x-2+2=0+2
2x=-3 3x=2
x=-3/2 x=2/3
x=-1,5
L'équation a deux solutions: x = -1,5 et 2/3