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Knssd
@Knssd
May 2019
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Bonjour besoin d side pour cet exercice svp merci d avance
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Verified answer
1)
a) lecture du graphique : -1 et 3
b) k(-1) = (-1)² - 2(-1) - 3 = 1 + 2 - 3 = 0
k(3) = 3² - 2(3) - 3 = 9 - 6 - 3 = 0
2) k(x) ≥ 0 quand x ≤ -1 et x ≥ 3
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Verified answer
1)a) lecture du graphique : -1 et 3
b) k(-1) = (-1)² - 2(-1) - 3 = 1 + 2 - 3 = 0
k(3) = 3² - 2(3) - 3 = 9 - 6 - 3 = 0
2) k(x) ≥ 0 quand x ≤ -1 et x ≥ 3