January 2021 0 57 Report
BONJOUR BESOIN D'AIDE ! Sachant que 1 ! = 1 ; 2 !=2×1 ; 3 ! = 3×2×1 et n ! = n×(n-1)×...×1,
déterminer le reste de la division de 1 !+2 !+3 !+ …+98 !+99 !+100 ! par 18
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