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B3RS3RK3R
@B3RS3RK3R
June 2021
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Bonjour, besoin d'aide URGENCE.
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prenons le repère A,AB,AC
A(0;0)
B(1;0)
C(0;1)
K(2/3;1/3)
BK(2/3-1;1/3-0): (-1/3;1/3)
BC(-1;1)
-1*1/3=1*-1/3
donc BK et BC colinéaires, donc B,K,C alignés
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prenons le repère A,AB,AC
A(0;0)
B(1;0)
C(0;1)
K(2/3;1/3)
BK(2/3-1;1/3-0): (-1/3;1/3)
BC(-1;1)
-1*1/3=1*-1/3
donc BK et BC colinéaires, donc B,K,C alignés