bonjour
A = (5x)²-2² - (5x*4x+5x*1-2*4x-2*1) (a-b) (a-b)²=a²-b²
= 25x²-4 - (20x²-3x-2)
= 5x² +3x - 2
puis
A = (5x-2) (5x+2) - (5x-2) (4x+1)
= (5x-2) [(5x+2)-(4x+1)]
= (5x-2) (x+1)
et
B sous la forme a²-b² qui se factorise par (a+b) (a-b)
donc B = (3x-1+6) (3x-1-6) = (3x+5)(3x-7)
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bonjour
A = (5x)²-2² - (5x*4x+5x*1-2*4x-2*1) (a-b) (a-b)²=a²-b²
= 25x²-4 - (20x²-3x-2)
= 5x² +3x - 2
puis
A = (5x-2) (5x+2) - (5x-2) (4x+1)
= (5x-2) [(5x+2)-(4x+1)]
= (5x-2) (x+1)
et
B sous la forme a²-b² qui se factorise par (a+b) (a-b)
donc B = (3x-1+6) (3x-1-6) = (3x+5)(3x-7)