Bonjour,
a)
A=
3(x+1) + 10 (x+1) (x-2)
b)
on factorise:
10 (x-2) = 10x -20
=> (x+1) ( 3 +10 x -20)
(x+1) (10x -17)
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Bonjour,
a)
A=
3(x+1) + 10 (x+1) (x-2)
b)
on factorise:
10 (x-2) = 10x -20
=> (x+1) ( 3 +10 x -20)
(x+1) (10x -17)