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Claradu66
@Claradu66
April 2019
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Bonjour, c'est niveau 4 ème . Je n'arrive pas à l'exercice 52 et 53. Merci de bien vouloir m'aider ☺
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Bonjour,
exo 52 :
dans BAC rectangle en A
d'après le codage AB=AC
BC² = AB²+AC²
= 4²+4²
= 32
on calcule CD dans DBC rectangle en B
CD² = BC²+BD²
= 32+2²
= 36
CD = √36 = 6cm
exo 53 :
A ATR =(TR*AH)/2
on calcule AH dans AHR rectangle en H
AR² = AH²+HR²
5,2² = AH²+2,9²
AH² = 5,2²-2,9²
= 18,63
AH = √8,63 ≈4,32cm
A = (8,4*4,32)/2
= 36,28/2 =18,14cm²
1 votes
Thanks 1
claradu66
Merci beaucoup
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Verified answer
Bonjour,exo 52 :
dans BAC rectangle en A
d'après le codage AB=AC
BC² = AB²+AC²
= 4²+4²
= 32
on calcule CD dans DBC rectangle en B
CD² = BC²+BD²
= 32+2²
= 36
CD = √36 = 6cm
exo 53 :
A ATR =(TR*AH)/2
on calcule AH dans AHR rectangle en H
AR² = AH²+HR²
5,2² = AH²+2,9²
AH² = 5,2²-2,9²
= 18,63
AH = √8,63 ≈4,32cm
A = (8,4*4,32)/2
= 36,28/2 =18,14cm²