Articles
Register
Sign In
Search
CANDETHA
@CANDETHA
January 2021
1
49
Report
Bonjour,
Comment factoriser -8x²+6x+5
Please enter comments
Please enter your name.
Please enter the correct email address.
Agree to
terms and service
You must agree before submitting.
Send
Lista de comentários
anylor
Bonjour
si tu es en première
on utilise la méthode du discriminant
-8x²+6x+5 est de la forme ax²+bx +c
a=-8
b=6
c=5
delta = b²-4ac
=6²-4×-8×5
=196
x1 = (-b-√Δ)/2a
=(-6-√196)/(-8×2)
=5/4
x2 =(-b+√Δ)/2a
=(-6+√196)/(-8×2)
= -1/2
pour factoriser on utilise la formule
a(x-x1)(x-x2)
d'où la factorisation :
-8 (x- 5/4) (x+1/2)
et si on veut enlever les fractions
comme -8 = -4 × 2
- 4 ×(x+5/4) × 2(x+1/2)
= ( -4x + 5) (2x+1)
= - (4x-5) (2x+1)
1 votes
Thanks 1
CANDETHA
ah merci beauocup
anylor
je vérifie
CANDETHA
personnelement j'ai trouvé (-2x-1)(4x-5)
anylor
voilà c'est vérifié, ta réponse est ok, pas de souci
anylor
si on développe - (4x-5) (2x+1) on retrouve -8x²+6x+5
More Questions From This User
See All
CANDETHA
January 2021 | 0 Respostas
Responda
CANDETHA
January 2021 | 0 Respostas
Responda
×
Report "Bonjour, Comment factoriser -8x²+6x+5.... Pergunta de ideia de CANDETHA"
Your name
Email
Reason
-Select Reason-
Pornographic
Defamatory
Illegal/Unlawful
Spam
Other Terms Of Service Violation
File a copyright complaint
Description
Helpful Links
Sobre nós
Política de Privacidade
Termos e Condições
direito autoral
Contate-Nos
Helpful Social
Get monthly updates
Submit
Copyright © 2024 ELIBRARY.TIPS - All rights reserved.
Lista de comentários
si tu es en première
on utilise la méthode du discriminant
-8x²+6x+5 est de la forme ax²+bx +c
a=-8
b=6
c=5
delta = b²-4ac
=6²-4×-8×5
=196
x1 = (-b-√Δ)/2a
=(-6-√196)/(-8×2)
=5/4
x2 =(-b+√Δ)/2a
=(-6+√196)/(-8×2)
= -1/2
pour factoriser on utilise la formule
a(x-x1)(x-x2)
d'où la factorisation :
-8 (x- 5/4) (x+1/2)
et si on veut enlever les fractions
comme -8 = -4 × 2
- 4 ×(x+5/4) × 2(x+1/2)
= ( -4x + 5) (2x+1)
= - (4x-5) (2x+1)