bonjour
A ( 1) = 4 et A ( 3 ) = 6
( 6 - 4 ) : ( 3 - 1 ) = 2/2 = 1 ⇔ ax = x
A (1) = 4
1 * 1 + b = 4 ⇔ b = 4 - 1 = 3
f (x) = x + 3
*********************************************************************************************
B ( 2) = 4 et B ( 3 ) = 7
( 7 - 4 ) : ( 3 - 2 ) = 3/1 = 3 ⇔ ax = 3 x
B (2) = 4
2 * 3 + b = 4 ⇔ b = 4 - 6 = - 2
g (x) = 3 x - 2
continue, tu fais les mêmes calculs pour les autres
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bonjour
A ( 1) = 4 et A ( 3 ) = 6
( 6 - 4 ) : ( 3 - 1 ) = 2/2 = 1 ⇔ ax = x
A (1) = 4
1 * 1 + b = 4 ⇔ b = 4 - 1 = 3
f (x) = x + 3
*********************************************************************************************
B ( 2) = 4 et B ( 3 ) = 7
( 7 - 4 ) : ( 3 - 2 ) = 3/1 = 3 ⇔ ax = 3 x
B (2) = 4
2 * 3 + b = 4 ⇔ b = 4 - 6 = - 2
g (x) = 3 x - 2
continue, tu fais les mêmes calculs pour les autres