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LutineEmeline
@LutineEmeline
June 2021
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Bonjour, est ce que quelqu'un peut m'aider s'il vous plait je ne comprends pas du tout merci
(exercice en pièce jointe)
niveau 3eme sur les racines carrés, la factorisation...
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slyz007
Verified answer
B=4x²-9-(2x+3)(x-1)
B=4x²-9-(2x²-2x+3x-3)
B=4x²-9-2x²-x+3
B=2x²-x-6
4x²-9=(2x)²-3²=(2x+3)(2x-3)
B=(2x+3)(2x-3)-(2x+3)(x-1)
B=(2x+3)((2x-3)-(x-1))
B=(2x+3)(x-2)
(2x+3)(x-2)=0
⇔2x+3=0 ou x-2=0
⇔x=-3/2 ou x=2
si x=
B=2*5-
-6=4-
2 votes
Thanks 1
LutineEmeline
merci
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Verified answer
B=4x²-9-(2x+3)(x-1)B=4x²-9-(2x²-2x+3x-3)
B=4x²-9-2x²-x+3
B=2x²-x-6
4x²-9=(2x)²-3²=(2x+3)(2x-3)
B=(2x+3)(2x-3)-(2x+3)(x-1)
B=(2x+3)((2x-3)-(x-1))
B=(2x+3)(x-2)
(2x+3)(x-2)=0
⇔2x+3=0 ou x-2=0
⇔x=-3/2 ou x=2
si x=
B=2*5--6=4-