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Lu1999
@Lu1999
April 2019
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Bonjour,
Est ce que quelqu'un peut me résoudre l'équation suivante :
X^2-3X+1=0
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Commentaires (2)
X² - 3x + 1 = 0
Δ = b² - 4ac
= (- 3)² - 4 x 1 x 1
= 9 - 4
= 5
Comme Δ > 0 l'équation a deux solutions.
x = (- b - √Δ) / 2a =
(3 - √5) / 2
ou
x = (- b + √Δ) / 2a =
(3 + √5) / 2
1 votes
Thanks 2
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lu1999
June 2021 | 0 Respostas
Bonjour Savez vous comment on calcule un point d'intersection d'une droite et d'une parabole ???
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Δ = b² - 4ac
= (- 3)² - 4 x 1 x 1
= 9 - 4
= 5
Comme Δ > 0 l'équation a deux solutions.
x = (- b - √Δ) / 2a = (3 - √5) / 2
ou
x = (- b + √Δ) / 2a = (3 + √5) / 2