5x²+x-7 = 2x-7
5x²+x-7-2x+7 =0
5x²-x = 0
x(5x-1) =0
donc
x =0 et 5x-1 =0
x = 1/5
solution (0;1/5)
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Verified answer
5x²+x-7 = 2x-7
5x²+x-7-2x+7 =0
5x²-x = 0
x(5x-1) =0
donc
x =0 et 5x-1 =0
x = 1/5
solution (0;1/5)
Verified answer
Bonjour5 x² +x - 7 = 2 x - 7
5 x² + x - 2 x = - 7 + 7
5 x² - x = 0
x ( 5 x - 1) = 0
pour q'une équation produit soit nulle, il suffit que l'un des facteurs le soit
soit x = 0
soit 5 x -1 = 0
5 x = 1
x = 1/5