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dmxrgxt
@dmxrgxt
January 2021
2
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Bonjour est-ce que quelqu’un pourrais me développer (x-2)(2x+3)-3(x-2) puis factoriser
Merci
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chipoune20003
Verified answer
Développer et factoriser
(x-2)(2x+3)-3(x-2) = 2x^2-4x
=
2(x-2)x
0 votes
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aur70
Verified answer
Bonjour
(x-2)(2x+3)-3(x-2)=2x²+3x-4x-6-3x+6=2x²-4x
(x-2)(2x+3)-3(x-2)=(x-2)(2x+3-3)=2x(x-2)
1 votes
Thanks 1
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Verified answer
Développer et factoriser(x-2)(2x+3)-3(x-2) = 2x^2-4x= 2(x-2)x
Verified answer
Bonjour(x-2)(2x+3)-3(x-2)=2x²+3x-4x-6-3x+6=2x²-4x
(x-2)(2x+3)-3(x-2)=(x-2)(2x+3-3)=2x(x-2)