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Sila91
@Sila91
May 2019
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Bonjour,
Exercice 50 page 121
Factoriser :
F = (4x + 5)(2x - 3) - (4x + 5)(5x + 2)
G = (3x + 2)² - (3x + 2)(5x - 4)
H = (4x + 5)² - (4x + 5)
Merci d'avance.
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swnn
F = (4x+5)[(2x-3)-(5x+2)]
F = (4x+5)[2x-3-5x-2]
F = (4x+5)(2x-3-5x-2)
F = (4x+5)(-3x-5)
G = (3x+2)(3x+2)-(3x+2)(5x-4)
G = (3x+2)[(3x+2)-(5x-4)]
G = (3x+2)[3x+2-5x+4]
G = (3x+2)(3x+2-5x+4)
G = (3x+2)(-2x+6)
H = (4x+5)(4x+5)-(4x+5)
H = (4x+5)[(4x+5)-1]
H = (4x+5)[4x+5-1]
H = (4x+5)(4x+5-1)
H = (4x+5)(4x+4)
2 votes
Thanks 1
Sila91
Merci, mais j'ai un problème pour G et H je ne vois pas le carré (²)
swnn
je n’ai pas réécris les carrés j’ai décomposé directement, puisque (3x+2)² = (3x+2)(3x+2) idem pour l’expression H :)
Sila91
Ah d'accord merci bcp
Sila91
Tu peux m'aider pour autre exercice ? merci
swnn
dis moi tout
Sila91
Ok Merci,
Sila91
Voilà, tu as vu ?
swnn
oui
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F = (4x+5)[2x-3-5x-2]
F = (4x+5)(2x-3-5x-2)
F = (4x+5)(-3x-5)
G = (3x+2)(3x+2)-(3x+2)(5x-4)
G = (3x+2)[(3x+2)-(5x-4)]
G = (3x+2)[3x+2-5x+4]
G = (3x+2)(3x+2-5x+4)
G = (3x+2)(-2x+6)
H = (4x+5)(4x+5)-(4x+5)
H = (4x+5)[(4x+5)-1]
H = (4x+5)[4x+5-1]
H = (4x+5)(4x+5-1)
H = (4x+5)(4x+4)