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Zoroastre
@Zoroastre
May 2019
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Bonjour
factorisation de: 4 x au carré -16+(2 x + 3) (x - 2)
réponse détaillée svp.
maths 3 ème
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nadiab
Verified answer
factorisation de: 4 x² -16 + (2 x + 3) (x - 2)
cela donne
(2x+4)(2x-4)+
(2 x + 3) (x - 2)
Pour avoir en facteur commun le (x-2)
4(x+2)(x-2)+(2x+3)(x-2)
Je factorise
(x-2)[4(x+2)+(2x+3)]
(x-2)(4x+8+2x+3)
(x-2)(6x+11)
2 votes
Thanks 1
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Verified answer
factorisation de: 4 x² -16 + (2 x + 3) (x - 2)cela donne
(2x+4)(2x-4)+(2 x + 3) (x - 2)
Pour avoir en facteur commun le (x-2)
4(x+2)(x-2)+(2x+3)(x-2)
Je factorise
(x-2)[4(x+2)+(2x+3)]
(x-2)(4x+8+2x+3)
(x-2)(6x+11)