Articles
Register
Sign In
Search
Pikachu972
@Pikachu972
May 2019
2
112
Report
Bonjour,
Factoriser, en un produit de trois polynomes de degré 1, le polunome P(x)=4x^3 - 5x^2 -9x.
Résoudre l'équation P(x)=0
Please enter comments
Please enter your name.
Please enter the correct email address.
Agree to
terms and service
You must agree before submitting.
Send
Lista de comentários
aymanemaysae
Bonsoir ;
P(x) = 4x^3 - 5x² - 9x = x(4x² - 5x - 9) = x(4x² + 4x - 9x - 9)
= x(4x(x + 1) - 9(x + 1)) = x((x + 1)(4x - 9)) = x(x + 1)(4x - 9) .
P(x) = 0 ==> x(x + 1)(4x - 9) = 0
==> x = 0 ou x + 1 = 0 ou 4x - 9 = 0
==> x = 0 ou x = - 1 ou x = 9/4 .
0 votes
Thanks 0
Pikachu972
vous allez trop vite je ne comprends pas
Pikachu972
P(x) = 4x^3 - 5x² - 9x = x(4x² - 5x - 9) je suis d'accord mais après je ne sais pas pourquoi vous décomposez le 5x en 4x-9x
MAHAM
Bonsoir
p(x)=4x³-5x²-9x
P(x)=x(4x²-5x-9) avec 4x²-5x-9=4(x+1)(x-9/4)
p(x)=4x(x+1)(x-9/4)
p(x)=0⇔4x(x+1)(x-9/4)=0
⇔4x=0 ou x+1=0 ou x-9/4=0
⇔x=0 ou x=-1 ou x=9/4
1 votes
Thanks 0
More Questions From This User
See All
Pikachu972
February 2021 | 0 Respostas
Responda
Pikachu972
February 2021 | 0 Respostas
Responda
Pikachu972
February 2021 | 0 Respostas
Responda
Pikachu972
February 2021 | 0 Respostas
Responda
Pikachu972
February 2021 | 0 Respostas
Bonjour , je n' arrive pas , votre aide sera la bien venue !
Responda
Pikachu972
February 2021 | 0 Respostas
Responda
Pikachu972
February 2021 | 0 Respostas
Responda
Pikachu972
February 2021 | 0 Respostas
Responda
Pikachu972
January 2021 | 0 Respostas
Responda
Pikachu972
January 2021 | 0 Respostas
Responda
×
Report "Bonjour, Factoriser, en un produit de trois polynomes de degré 1, le polunome P(x)=4x^3 - 5x^2 -9x.... Pergunta de ideia de Pikachu972"
Your name
Email
Reason
-Select Reason-
Pornographic
Defamatory
Illegal/Unlawful
Spam
Other Terms Of Service Violation
File a copyright complaint
Description
Helpful Links
Sobre nós
Política de Privacidade
Termos e Condições
direito autoral
Contate-Nos
Helpful Social
Get monthly updates
Submit
Copyright © 2024 ELIBRARY.TIPS - All rights reserved.
Lista de comentários
P(x) = 4x^3 - 5x² - 9x = x(4x² - 5x - 9) = x(4x² + 4x - 9x - 9)
= x(4x(x + 1) - 9(x + 1)) = x((x + 1)(4x - 9)) = x(x + 1)(4x - 9) .
P(x) = 0 ==> x(x + 1)(4x - 9) = 0
==> x = 0 ou x + 1 = 0 ou 4x - 9 = 0
==> x = 0 ou x = - 1 ou x = 9/4 .
p(x)=4x³-5x²-9x
P(x)=x(4x²-5x-9) avec 4x²-5x-9=4(x+1)(x-9/4)
p(x)=4x(x+1)(x-9/4)
p(x)=0⇔4x(x+1)(x-9/4)=0
⇔4x=0 ou x+1=0 ou x-9/4=0
⇔x=0 ou x=-1 ou x=9/4