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moreaulea
@moreaulea
January 2021
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Bonjour, il faut que je factorise 2 expressions, mais je n'y arrive vraiment pas...
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gcnew81
A(x) = 4(x+2)²-9(2x-1)²
A(x) = 2²(x+2)² - 3²(2x-1)²
a = 2(x+2), b = 3(2x-1)
A(x) = a²-b²
A(x) = (a+b)(a-b)
= (2(x+2) + 3(2x-1)) (2(x+2) - 3(2x-1))
= (2x+4 + 6x-3) ( 2x+4 -6x+3 )
= (8x+1)(-4x+7)
B(x) = (2x+7)(3x+6) - 2(2x+4)(2x-8)
B(x) = (2x+7)*3(x+2) - 2 *2(x+2)(2x-8)
= (x+2) [ 3(2x+7) - 4(2x-8) ] // Bon pour cette étape faut avoir le coup de main.
= (x+2) [ 6x+21 - 8x + 32 ]
= (x+2) (-2x +53)
1 votes
Thanks 1
moreaulea
MERCI BEAUCOUP ! tu me sauve !
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A(x) = 2²(x+2)² - 3²(2x-1)²
a = 2(x+2), b = 3(2x-1)
A(x) = a²-b²
A(x) = (a+b)(a-b)
= (2(x+2) + 3(2x-1)) (2(x+2) - 3(2x-1))
= (2x+4 + 6x-3) ( 2x+4 -6x+3 )
= (8x+1)(-4x+7)
B(x) = (2x+7)(3x+6) - 2(2x+4)(2x-8)
B(x) = (2x+7)*3(x+2) - 2 *2(x+2)(2x-8)
= (x+2) [ 3(2x+7) - 4(2x-8) ] // Bon pour cette étape faut avoir le coup de main.
= (x+2) [ 6x+21 - 8x + 32 ]
= (x+2) (-2x +53)