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Shymenapertshymen23
@Shymenapertshymen23
May 2019
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Bonjour
j'ai besoin d'aide pour l'exercice n°5 et 6 svp
merci
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chrystine
Bonsoir
a)dans le triangle SHA rectangle en H on a:
cos (HSA)=SH/SA
cos 60=SH/6
SH=6*cos(60)=3 cm
b)sin (HSA)=AH/SA
sin 60°=AH/6
AH=6*sin(60)≈5.20 cm
1 votes
Thanks 1
chrystine
De rien
marco31
Bonsoir
Exercice 5
A/ Cos 60°= SH/SA⇒SH=Cos 60°×6=3 cm
B/ tang 60°=AH/SH⇒AH=tang 60°×3=5,19 m
1 votes
Thanks 1
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Lista de comentários
a)dans le triangle SHA rectangle en H on a:
cos (HSA)=SH/SA
cos 60=SH/6
SH=6*cos(60)=3 cm
b)sin (HSA)=AH/SA
sin 60°=AH/6
AH=6*sin(60)≈5.20 cm
Exercice 5
A/ Cos 60°= SH/SA⇒SH=Cos 60°×6=3 cm
B/ tang 60°=AH/SH⇒AH=tang 60°×3=5,19 m