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Nicolasgruel
@Nicolasgruel
April 2019
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Bonjour j'ai besoin d'aide pour mon dm de maths merci d'avance.
On pose J(y) est égal à H(y) - I(y). Factoriser J(y)
Sachant que I(y)=(3y-8)(3y-6) et que H(y)= (3y-8)² S'il vous plait c'est pour 9 heures
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Bonjour
J(y) = (3y - 8)² -
(3y - 8)(3y - 6)
= (3y - 8)(3y - 8) - (3y - 8)(3y - 6)
= (3y - 8)[(3y - 8) - (3y - 6)]
= (3y - 8)(3y - 8 - 3y + 6)
= (3y - 8)(-2)
= -2(3y - 8)
1 votes
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J(y) = (3y - 8)² - (3y - 8)(3y - 6)
= (3y - 8)(3y - 8) - (3y - 8)(3y - 6)
= (3y - 8)[(3y - 8) - (3y - 6)]
= (3y - 8)(3y - 8 - 3y + 6)
= (3y - 8)(-2)
= -2(3y - 8)