a)
\frac{x-1}{2} = \frac{3x+1}{4}
4(x - 1) = 2(3x + 1)
4x - 4 = 6x + 2
-2x = 6
x = -3
b)
\frac{x}{3}+1= \frac{3x}{2}+2 \\ \frac{x+3}{3}= \frac{3x+4}{2} \\ 2(x+3) = 3(3x+4) \\ 2x + 6 = 9x + 12 \\ -7x = 6x = - \frac{6}{7}
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a)
\frac{x-1}{2} = \frac{3x+1}{4}
4(x - 1) = 2(3x + 1)
4x - 4 = 6x + 2
-2x = 6
x = -3
b)
\frac{x}{3}+1= \frac{3x}{2}+2 \\
\frac{x+3}{3}= \frac{3x+4}{2} \\
2(x+3) = 3(3x+4) \\
2x + 6 = 9x + 12 \\
-7x = 6
x = - \frac{6}{7}
je te laisse le dernier pour pratiquer
Contacte-moi si tu as de la difficulté