Articles
Register
Sign In
Search
Slower93
@Slower93
May 2019
2
26
Report
Bonjour, j'ai besoin d'aide pour un exercice de Maths.
Voir image ci-joint.
Merci d'avance
Please enter comments
Please enter your name.
Please enter the correct email address.
Agree to
terms and service
You must agree before submitting.
Send
Lista de comentários
nadaghellal
S=(2t-5)+(2t-5)(x-1)-x(t-5)
=2t-5+2tx-2t-5x+5-tx+5x
=tx
S=tx
=(3012/2507)×(2507/3012)
=7551084/7551084
=1
0 votes
Thanks 1
guestnosdevoir
Bonjour,☕️
__________________
____EXERCICE 9____
__________________
≡≡question a≡≡
____________
On développe :
S= (2t - 5) + (2t - 5)(x - 1) - x(t - 5)
S= (2t - 5) +[ (2t).x - 2t - 5x + 5 ] - tx + 5x
S= 2t - 5 + 2tx - 2t - 5x + 5 - tx + 5x
S= (2t - 2t) + (5 - 5) + (5x - 5x) + (2tx - tx)
S= (0) + (0) + (0) + (tx)
S= tx.
≡≡question b≡≡
____________
Pour x= (2 507÷3 012). et t= (3 012÷2 507)
On a :
S = tx = (2 507÷3 012)×(3 012÷2 507) = (2 507×3 012)÷(3 012×2 507) = 1.
:)
1 votes
Thanks 1
More Questions From This User
See All
Slower93
April 2022 | 0 Respostas
Responda
Slower93
January 2021 | 0 Respostas
Responda
Slower93
January 2021 | 0 Respostas
Responda
Slower93
January 2021 | 0 Respostas
Responda
Slower93
January 2021 | 0 Respostas
Bonjour, Dans quelles circonstances Tristan et Iseut absorbent-ils le breuvage magique ?
Responda
Slower93
January 2021 | 0 Respostas
Bonjour, j'ai besoin d'aide Merci d'avance
Responda
Slower93
January 2021 | 0 Respostas
Bonjour, j'ai besoin d'aideMerci d'avance
Responda
Slower93
January 2021 | 0 Respostas
Bonsoir, j'ai besoin d'aideMerci d'avance.
Responda
Slower93
January 2021 | 0 Respostas
Responda
Slower93
January 2021 | 0 Respostas
Bonsoir, j'ai besoin d'aideMerci d'avance.
Responda
×
Report "Bonjour, j'ai besoin d'aide pour un exercice de Maths.Voir image ci-joint.Merci d'avance.... Pergunta de ideia de Slower93"
Your name
Email
Reason
-Select Reason-
Pornographic
Defamatory
Illegal/Unlawful
Spam
Other Terms Of Service Violation
File a copyright complaint
Description
Helpful Links
Sobre nós
Política de Privacidade
Termos e Condições
direito autoral
Contate-Nos
Helpful Social
Get monthly updates
Submit
Copyright © 2024 ELIBRARY.TIPS - All rights reserved.
Lista de comentários
=2t-5+2tx-2t-5x+5-tx+5x
=tx
S=tx
=(3012/2507)×(2507/3012)
=7551084/7551084
=1
__________________
____EXERCICE 9____
__________________
≡≡question a≡≡
____________
On développe :
S= (2t - 5) + (2t - 5)(x - 1) - x(t - 5)
S= (2t - 5) +[ (2t).x - 2t - 5x + 5 ] - tx + 5x
S= 2t - 5 + 2tx - 2t - 5x + 5 - tx + 5x
S= (2t - 2t) + (5 - 5) + (5x - 5x) + (2tx - tx)
S= (0) + (0) + (0) + (tx)
S= tx.
≡≡question b≡≡
____________
Pour x= (2 507÷3 012). et t= (3 012÷2 507)
On a :
S = tx = (2 507÷3 012)×(3 012÷2 507) = (2 507×3 012)÷(3 012×2 507) = 1.
:)