Bonjour,
a) Pythagore : OA² = OH² + HA² = (4/3)² + (3/2)² = 145/36
donc OA = √(145/36) ≅ 2 dm
b) volume = π × (3/2)² × 4/3 = 3π
c) OK = OH × 9/16 = 4/3 × 9/16 = 3/4 dm
KH = OH × (1 - 9/16) = 4/3 × 7/16 = 7/12 dm
d) la même que pour le cylindre C : 3/2 dm
e) V = π × (3/2)² × 3/4 = (27/16 × π) dm³
Copyright © 2024 ELIBRARY.TIPS - All rights reserved.
Lista de comentários
Bonjour,
a) Pythagore : OA² = OH² + HA² = (4/3)² + (3/2)² = 145/36
donc OA = √(145/36) ≅ 2 dm
b) volume = π × (3/2)² × 4/3 = 3π
c) OK = OH × 9/16 = 4/3 × 9/16 = 3/4 dm
KH = OH × (1 - 9/16) = 4/3 × 7/16 = 7/12 dm
d) la même que pour le cylindre C : 3/2 dm
e) V = π × (3/2)² × 3/4 = (27/16 × π) dm³