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Karim3em
@Karim3em
May 2019
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Bonjour j'ai quelques problèmes avec mes 3 derniers calculs algébriques de mon DM.
(2x+3)(8x+1)
(9x-4)(5x-7)
(3x-4)²
En me donnant la réponse expliquez moi comment avez-vous fait.
Merci d'avance.
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Bonjour,
il faut développer, * = multiplier
(2x+3)(8x+1) =
2x*8x + 2x*1 + 3*8x + 3*1 =
tu finis
(9x-4)(5x-7) =
9x*5x + 9x*-7 -4*5x -4*-7 =
(3x-4)² = (a-b)² =a²-2ab+b² = à savoir par coeur
(3x)²-2(3x*4)+4² =
9x²-24x+16
1 votes
Thanks 0
nadiab
(2x+3)(8x+1)
tu distribues
16x²+24x+2x+3
tu réduis
16x²+26x+3
(9x-4)(5x-7)
45x²-20x+63x+28
45x²-43x+28
(3x-4)²
(3x-4)(3x-4)
9x²-12x-12x+16
9x²-24x+16
1 votes
Thanks 0
karim3em
@zetom J'étais bien parti pour la première expression
karim3em
;)
karim3em
il* ...
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Verified answer
Bonjour,il faut développer, * = multiplier
(2x+3)(8x+1) =
2x*8x + 2x*1 + 3*8x + 3*1 =
tu finis
(9x-4)(5x-7) =
9x*5x + 9x*-7 -4*5x -4*-7 =
(3x-4)² = (a-b)² =a²-2ab+b² = à savoir par coeur
(3x)²-2(3x*4)+4² =
9x²-24x+16
tu distribues
16x²+24x+2x+3
tu réduis
16x²+26x+3
(9x-4)(5x-7)
45x²-20x+63x+28
45x²-43x+28
(3x-4)²
(3x-4)(3x-4)
9x²-12x-12x+16
9x²-24x+16