1.theoreme de Pythagore:
ac²=ah²+ch²
5,10²=4,5²+ch²
26,01=20,25+ch²
ch²=26,01-20,25
ch²=5,76
ch=racine carre de 5,76
ch=2,4m
2. aire abc=4,5×2,4 = 10,8m²
3. 15×9×3=405m³
+2,4×2,4×15=86,4m³
volume total de la serre=405m³+86,4m³=491,4m³
4. x= montant annuel cahiffage
x=950×491,4÷350
x=1333,8€
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1.theoreme de Pythagore:
ac²=ah²+ch²
5,10²=4,5²+ch²
26,01=20,25+ch²
ch²=26,01-20,25
ch²=5,76
ch=racine carre de 5,76
ch=2,4m
2. aire abc=4,5×2,4 = 10,8m²
3. 15×9×3=405m³
+2,4×2,4×15=86,4m³
volume total de la serre=405m³+86,4m³=491,4m³
4. x= montant annuel cahiffage
x=950×491,4÷350
x=1333,8€