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Pablodaynes
@Pablodaynes
April 2019
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Bonjour, j'ai un DM en maths et j'ai besoin d'aide... :) merci d'avance
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nadouda12
F=(10x-5)(x+2)+(1-x)(2x-1)
f=5(2x-1)(x+2)+(1-x)(2x-1)
f=(2x-1)[5(x+2)+(2x-1)]
f=(2x-1)[5x+10+2x-1]
f=(2x-1)(7x+9)
g=(4x+4)(1-2x)+(x+1)puissance 2
g=4(x+1)(1-2x)+(x+1)(x+1)
g=(x+1)[4(1-2x)+(x+1)]
g=(x+1)(4-8x+x+1)
g=(x+1)(5-7x)
h=(2x+1)puissance 2 -(x+3)(10x+5)
h=(2x+1)(2x+1)-(x+3)5(2x+1)
h=(2x+1)[2x+1-(x+3)]
h=(2x+1)(2x+1-x-3)
h=(2x+1)(x-2)
0 votes
Thanks 1
nadouda12
avec plaisir est ce que c'est correcte ??
isapaul
Non pas tout à fait car F = 5(2x-1)(x+2) + (1-x)(2x-1)
isapaul
f = (2x-1)(5(x+2) + (1-x)] = (2x-1)[ (5x+10) + (1-x) ] = (2x-1) ( 5x+10-1+x) = (2x-1)(6x +9)
isapaul
h = (2x+1)(2x+1) - (x+3)(5)(2x+1)= (2x+1)[ (2x+1) - 5(x+3)] = (2x+1)( 2x+1-5x-15) = (2x+1)(-3x - 14)
nadouda12
aahh ok je suis dsl
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f=5(2x-1)(x+2)+(1-x)(2x-1)
f=(2x-1)[5(x+2)+(2x-1)]
f=(2x-1)[5x+10+2x-1]
f=(2x-1)(7x+9)
g=(4x+4)(1-2x)+(x+1)puissance 2
g=4(x+1)(1-2x)+(x+1)(x+1)
g=(x+1)[4(1-2x)+(x+1)]
g=(x+1)(4-8x+x+1)
g=(x+1)(5-7x)
h=(2x+1)puissance 2 -(x+3)(10x+5)
h=(2x+1)(2x+1)-(x+3)5(2x+1)
h=(2x+1)[2x+1-(x+3)]
h=(2x+1)(2x+1-x-3)
h=(2x+1)(x-2)