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Filleintelligente
@Filleintelligente
April 2019
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Bonjour, j'ai un DM en maths mais je n'arrive pas à résoudre un exercice.
On a B(x;0).
Je n'arrive pas à résoudre (x+0,5)(-x+2,5)=0 et -(x-1)²+2,25=0
Pourriez vous m'aider s'il vous plaît ?
Merci
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nonotata
(x+0,5)(-x+2,5)=0
x+0.5 = 0 -x +2.5 = 0
x = -0.5 -x = -2.5
x = -1/2 x = 2.5 = 25/10 = 5/2
-(x-1)²+2,25=0
-(x-1)² + 1.125² = 0
- (x-1 +1.125) (x-1+1.125) = 0
-(x +0.125) (x +0.125) = 0
-x -0.125 = 0 ou x +0.125 =0
-x = 0.125 x = -0.125
x = 0.125
donc une sule solution x = 0.125 = 125/1000 = 25/200 = 5/ 40
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x+0.5 = 0 -x +2.5 = 0
x = -0.5 -x = -2.5
x = -1/2 x = 2.5 = 25/10 = 5/2
-(x-1)²+2,25=0
-(x-1)² + 1.125² = 0
- (x-1 +1.125) (x-1+1.125) = 0
-(x +0.125) (x +0.125) = 0
-x -0.125 = 0 ou x +0.125 =0
-x = 0.125 x = -0.125
x = 0.125
donc une sule solution x = 0.125 = 125/1000 = 25/200 = 5/ 40