bonjour,
50 x > x² - 10 x + 500
- x² + 10 x + 50 x > 500
- x² + 60 x > 5 00
- x² + 60 x - 500 > 0
on cherche les valeurs pour lesquelles = 0
- x² + 60 x - 500 = 0
Δ = 60 ² - 4 ( - 1 * - 500)
Δ = 3 600 - 2 000 = 1 600
x 1 = ( - 60 - 40) / - 2 = - 100 / - 2 = 50
x 2 = ( - 60 + 40 ) / - 2 = - 20 / - 2 = 10
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bonjour,
50 x > x² - 10 x + 500
- x² + 10 x + 50 x > 500
- x² + 60 x > 5 00
- x² + 60 x - 500 > 0
on cherche les valeurs pour lesquelles = 0
- x² + 60 x - 500 = 0
Δ = 60 ² - 4 ( - 1 * - 500)
Δ = 3 600 - 2 000 = 1 600
x 1 = ( - 60 - 40) / - 2 = - 100 / - 2 = 50
x 2 = ( - 60 + 40 ) / - 2 = - 20 / - 2 = 10