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77math77
@77math77
January 2021
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Bonjour, j'ai vraiment besoin d'aide svp. C'est urgent. 20 points sur cet exercice
Merci d'avance.
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Christine17
EX51
1X3=3
2X1=2
2X3=6
Les diviseurs de 6 sont 1,2,3 et 6.
2a)
105
diviseurs :
1 car 1X105=105
3 car 3X35=105
5 car 5X21=105
7 car 7x15=105
15
21
35
105
3 votes
Thanks 7
77math77
Pour la 2.b. je fais comment pour l'arbre analogue ? Merci
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Bonjour tout le monde j'ai besoin de vous c'est important. Merci d'avance.
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Lista de comentários
1X3=3
2X1=2
2X3=6
Les diviseurs de 6 sont 1,2,3 et 6.
2a)
105
diviseurs :
1 car 1X105=105
3 car 3X35=105
5 car 5X21=105
7 car 7x15=105
15
21
35
105