Articles
Register
Sign In
Search
kazuaaa
@kazuaaa
November 2023
1
49
Report
bonjour j’aimerais bien de l’aide !!(exercice en entier)
Please enter comments
Please enter your name.
Please enter the correct email address.
Agree to
terms and service
You must agree before submitting.
Send
Lista de comentários
Jujuuuuuuuuuuuuu
Verified answer
Bonjour,
1a. λ=c/ν
1b. v=c/lambda=(3 x 10^8)/[580 x 10^(-9)]
=5,17 x 10^(14) Hz = 517 THz (T veut dire téra : 10^12)
2a. DeltaE = hc/lambda avec c = 3 x 10^8 m/s
= (6,63 x 10^-34)x(3x10^8)]/[580 x 10^(-9)]
= 3,429 x 10^(-19) J
2b. E = (6.63 * 10-34) * ((3.00* 108)/ (580 * 10 9))
= 3.43 * 10-19J
2c. en eV : DeltaE= [3,429 x 10^(-19)]/(1,602 x 10^(-19)]
= 2,14 eV
J’espère t’avoir aider !! :)
1 votes
Thanks 1
kazuaaa
merci beaucoup !
More Questions From This User
See All
kazuaaa
October 2023 | 0 Respostas
Responda
kazuaaa
February 2023 | 0 Respostas
Responda
kazuaaa
April 2022 | 0 Respostas
Responda
×
Report "bonjour j’aimerais bien de l’aide !!(exercice en entier).... Pergunta de ideia de kazuaaa"
Your name
Email
Reason
-Select Reason-
Pornographic
Defamatory
Illegal/Unlawful
Spam
Other Terms Of Service Violation
File a copyright complaint
Description
Helpful Links
Sobre nós
Política de Privacidade
Termos e Condições
direito autoral
Contate-Nos
Helpful Social
Get monthly updates
Submit
Copyright © 2024 ELIBRARY.TIPS - All rights reserved.
Lista de comentários
Verified answer
Bonjour,1a. λ=c/ν
1b. v=c/lambda=(3 x 10^8)/[580 x 10^(-9)]
=5,17 x 10^(14) Hz = 517 THz (T veut dire téra : 10^12)
2a. DeltaE = hc/lambda avec c = 3 x 10^8 m/s
= (6,63 x 10^-34)x(3x10^8)]/[580 x 10^(-9)]
= 3,429 x 10^(-19) J
2b. E = (6.63 * 10-34) * ((3.00* 108)/ (580 * 10 9))
= 3.43 * 10-19J
2c. en eV : DeltaE= [3,429 x 10^(-19)]/(1,602 x 10^(-19)]
= 2,14 eV
J’espère t’avoir aider !! :)