bjr
ex 4
P = x*x + x*2 + 12*x + 12* 2 = x² + 2x + 12x + 24 = x² + 14x + 24
Q= (x+7)² - 5² = (x+7 +5) (x+7 - 5) = (x+12) (x+2)
puisque a² - b² = (a+b) (a-b)
C
x+7
A 5 B
selon pythagore tu auras
BC² = AC² + AB²
donc AC² = BC² - AB² = (x+7)² - 5² = x² + 14x + 49 - 25 = x² + 14x + 24
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bjr
ex 4
P = x*x + x*2 + 12*x + 12* 2 = x² + 2x + 12x + 24 = x² + 14x + 24
Q= (x+7)² - 5² = (x+7 +5) (x+7 - 5) = (x+12) (x+2)
puisque a² - b² = (a+b) (a-b)
C
x+7
A 5 B
selon pythagore tu auras
BC² = AC² + AB²
donc AC² = BC² - AB² = (x+7)² - 5² = x² + 14x + 49 - 25 = x² + 14x + 24